It is paired with nesting () and crossing () helpers. Create a data frame from all combinations of the supplied vectors or factors. See the description of the return value for precise details of logical specifying if character vectors are Basically, it does the same kind of reshaping but in one way. Chambers, J. M. and Hastie, T. J. a logical indicating the "out.attrs" My question is how to create such a data frame. [which creates all possible pairs] and extract only those. Listen now. expand () generates all combination of variables found in a dataset. Hi! I've a data frame with n rows, and I want to apply a function on all possible combinations of k rows of this data frame. Full reprex below. See the description of the return value for precise details of the way this is done. Conversion to a factor is done with levels in the order In the next, and final section, I’ll show you how to apply some basic stats in R. Applying Basic Stats in R. Once you created the DataFrame, you can apply different computations and statistical analysis to your data. Actually, these two methods are slower (see below in reprex), and I won't gain anything other than learning a new alternative (which is important, I understand). Based on this answer on SO, I can do this using base R. (provided below). converted to factors. Generate All Combinations of n Elements, Taken m at a Time Description. Usage expand.grid(..., KEEP.OUT.ATTRS … they occur in the character vectors (and not alphabetically, as is factors. Cheers! expand () is often useful in conjunction with joins: components of a list. Usage expand.grid(..., KEEP.OUT.ATTRS = TRUE, stringsAsFactors = TRUE) Arguments... vectors, factors or a list containing these. But I fail to find patterns for higher values of k. Created on 2019-03-23 by the reprex package (v0.2.1). If x is a positive integer, returns all combinations of the elements of seq(x) taken m at a time. But I'm trying to learn tidyverse and hence I wonder whether there's a way to do this in tidyverse. Wadsworth & Brooks/Cole. Create a data frame from all combinations of the supplied vectors or factors. There is also a way with less steps but more cryptic and advanced as it uses the power of purrr::pmap(). Can these two be modified to perform better? Statistical Models in S. See the description of the return value for precise details of the way this is done. See the description of the return value for precise details of the way this is done. New replies are no longer allowed. Viewed 50k times 29. data: A data frame.... Specification of columns to expand. I was hoping for a direct approach via tidyverse. But if I have to use combn, then I guess I'll prefer base approach, as I understand what it's doing much better, as of now. Attribute "out.attrs" is a list which gives the dimension and crossing () is a wrapper around expand_grid () that de-duplicates and sorts its inputs; nesting () is a helper that only finds combinations already present in the data. Create a data frame from all combinations of the supplied vectors or combn (package utils) for the generation I am trying to filter out the duplicates of a subset of columns from a dataframe in R. I am interested in filtering unique combinations of session, first, and last. Create a Data Frame from All Combinations of Factor Variables Description. As you can see, base approach is better than both tidy approaches, and pmap is better than map. If I can create another data frame which has \binom{n}{k} rows corresponding to the all possible row combinations,then I can simply use my function using apply on the rows.. My question is how to create such a data frame. There should be a total of 40 unique combinations in my dataframe. the factors if these are supplied as named arguments or named If x is a positive integer, returns all combinations of the elements of seq(x) taken m at a time. most common when converting to factors). The following is what my data looks like . Main task is the reshaping to meet you expected output shape. Created on 2019-03-24 by the reprex package (v0.2.1). Value. Sorry, it's not copy-paste friendly. I can find the relevant row numbers from the output of tidyr::crossing(., .) Generate all combinations of the elements of x taken m at a time. crossing () is a wrapper around expand_grid () that de-duplicates and sorts its inputs; nesting () is a helper that only finds combinations already present in the data. Create a Data Frame of all the Combinations of Vectors passed as Argument in R Programming – expand.grid() Function Last Updated: 05-06-2020 expand.grid() function in R Language is used to create a data frame with all the values that can be formed with the combinations of all the vectors or factors passed to the function as argument. How to filter for unique combination of columns from an R dataframe. Active 3 years, 7 months ago. Hello, I need to create a dataframe containing all possible combinations of three variables: SITE (101,102,103,104), WDAY (MON,TUE,WED,THR,FRI), and TOD (MORN, AFTN). of all combinations of n elements, taken m at a time. rdrr.io Find an R package R language docs Run R in your browser R Notebooks. I used expand.grid() successfully(?) But I suppose there's a better way and at least for me, the pattern of the row indices is not that obvious. See below: Powered by Discourse, best viewed with JavaScript enabled, Create all possible combinations of a data frame. A data frame containing one row for each combination of the supplied expand.Rd. To find all unique combinations of x, y and z, including those not present in the data, supply each variable as a separate argument: expand(df, x, y, z).. To find only the combinations that occur in the data, use nesting: expand(df, nesting(x, y, z)).. You can combine the two forms. The first factors vary fastest. Actually, I couldn't totally follow his approaches, but I can follow yours. For k = 2, it's pretty easy. If I can create another data frame which has \binom{n}{k} rows corresponding to the all possible row combinations,then I can simply use my function using apply on the rows. Here is a way using tidyverse. the way this is done. This topic was automatically closed 7 days after the last reply. Based on this answer on SO, I can do … Columns can be atomic vectors or lists. It is not more efficient I guess but it could be easier to read and to clarify the step. Create a data frame from all combinations of the supplied vectors or factors. vectors, factors or a list containing these. You can also try this tidyverse alternative. It is paired with nesting () and crossing () helpers. (1992) attribute (see below) should be computed and returned. The row names are ‘automatic’. After you created the DataFrame in R, using either of the above methods, you can then apply some statistical analysis. It's much faster than the previous solution by Christophe. Create a data frame from all combinations of the supplied vectors or factors. Generate All Combinations of n Elements, Taken m at a Time Description. dimnames for use by predict methods. It turns out to be faster than the base-R approach too. I tried with a dataframe of 20 rows and 7 groups, and the time difference is really significant. I've a data frame with n rows, and I want to apply a function on all possible combinations of k rows of this data frame.. Please use reprex::reprex_rescue() for this part. Ask Question Asked 8 years, 11 months ago. 6. I'm not sure how it performs relative to base R, but I typically prefer the most readable and/or compact option unless I'm optimizing a bottleneck. expand () is often useful in conjunction with joins: The columns are labelled by If you have a query related to it or one of the replies, start a new topic and refer back with a link. factors. expand () generates all combination of variables found in a dataset. Usage expand.grid(..., KEEP.OUT.ATTRS = TRUE) Arguments... vectors, factors or a list containing these. Create a Data Frame from All Combinations of Factor Variables Description. Hi! Generate all combinations of the elements of x taken m at a time. See the description of the return value for precise details of the way this is done. KEEP.OUT.ATTRS: a logical indicating the "out.attrs" attribute (see below) should be computed and returned. 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